x^2+(2x-3)^2+6x-2(2x-3)=10

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Solution for x^2+(2x-3)^2+6x-2(2x-3)=10 equation: 



x^2+(2x-3)^2+6x-2(2x-3)=10

We move all terms to the left:

x^2+(2x-3)^2+6x-2(2x-3)-(10)=0

We add all the numbers together, and all the variables

x^2+6x+(2x-3)^2-2(2x-3)-10=0

We multiply parentheses

x^2+6x+(2x-3)^2-4x+6-10=0

We add all the numbers together, and all the variables

x^2+2x+(2x-3)^2-4=0

We move all terms containing x to the left, all other terms to the right

x^2+2x+(2x-3)^2=4

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